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What was that about moving coordinate frames?

We'll actually be covering more about this later, I think. In the conveyer belt problem, we considered the velocity of the mass in the frame of the factory (imagine you are on the floor and looking at the crate and conveyer belt). In this frame the crate starts with zero velocity when it's dropped onto the belt and ends up with some velocity with respect to you. In contrast, you could consider the frame of the belt: imagine you are sitting on the belt. In that frame, the crate would start with velocity $v$ (away from you) when it is dropped, and then reach the same velocity as the belt-- so it would end up with zero velocity with respect to you.

In the frame of the belt, as the crate comes to rest with respect to the belt, it's moving with respect to the belt (decelerated by friction). We calculated the distance it moved.

(If there were no friction, the crate would have zero velocity with respect to the floor after dropping. The belt would just slip under it. It would maintain velocity $v$ with respect to the belt.)


next up previous
Next: Why can we assume Up: Content Questions Previous: How did you determine
Kate Scholberg 2015-02-10