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How did you get from $-\int_1^2 (\nabla U) \cdot d\vec{r} = - \int_1^2 dU$?

For this we used the property of the gradient, $df = (\nabla f)\cdot d
\vec{r}$. Using this, wrote $(\nabla U) \cdot d\vec{r}$ as $dU$.



Kate Scholberg 2020-01-21