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There is a displacement node at the closed end, and an antinode at the
open end. This is just like a string fixed at one end and free at the
other. Let's arbitrarily make the closed end. Then:
|
(185) |
has a node at for all . To get an antinode at the other end,
we require:
|
(186) |
or
|
(187) |
for (odd half-integral multiples of . This converts
to:
|
(188) |
and
|
(189) |
Next: Pipe Open at Both
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Robert G. Brown
2004-04-12